Kinh tế lượngTrắc nghiệm

500 câu trắc nghiệm Kinh tế lượng – 11C

Tổng hợp 500 câu trắc nghiệm + tự luận Kinh tế lượng (Elementary Statistics). Tất cả các câu hỏi trắc nghiệm + tự luận đều có đáp án. Nội dung được khái quát trong 13 phần, mỗi phần gồm 3 bài kiểm tra (A, B, C). Các câu hỏi trắc nghiệm + tự luận bám rất sát chương trình kinh tế lượng, đặc biệt là phần thống kê, rất phù hợp cho các bạn củng cố và mở rộng các kiến thức về Kinh tế lượng. Các câu hỏi trắc nghiệm + tự luận của phần 11C bao gồm:

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. Provide an appropriate response.
1) List the assumptions for testing hypotheses that three or more means are equivalent.

1) The populations have approximately normal distributions.
2) The populations have the same variance \({\sigma ^2}\) (or standard deviation \(\sigma \)).
3) The samples are random and independent of each other.
4) The different samples are from populations that are categorized in only one way. (The requirements of normality and equal variances are somewhat relaxed.)

2) The test statistic for one-way ANOVA is F = (variance between samples)/(variance within samples). Describe variance within samples and variance between samples. What relationship between variance within samples and variance between samples would result in the conclusion that the value of F is significant?

Variance between samples measures the variation between the sample means of the groups treated differently, that is the variation due to the treatment. The variance within the samples depends solely on the sample variances of the groups treated alike. The F ratio compares the two. If the F ratio is relatively close to 1, the two variances are about the same, and we conclude that there are no significant differences among the sample means. When the value of F is excessively large (that is, greater than 1), we conclude that the variation among the samples is not the same and that the means are not equal.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean.

3)

SourceDFSSMSFp
Factor33010.001.60.264
Error8506.25
Total1180

Find the critical value.
○ 7.59
○ 8.85
○ 1.6
● 4.07

4)

SourceDFSSMSFp
Factor33010.001.60.264
Error8506.25
Total1180

Identify the p-value.
○ 1.6
○ 10.00
○ 6.25
● 0.264

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.
Test the claim that the samples come from populations with the same mean. Assume that the populations are normally distributed with the same variance.
5) The data below represent the weight losses for people on three different exercise programs.

Exercise AExercise BExercise C
2.55.84.3
8.84.96.2
7.31.15.8
9.87.88.1
5.11.27.9

At the 1% significance level, does it appear that a difference exists in the true mean weight loss produced by the three exercise programs?

Test statistic: F = 1.491. Critical value: F = 6.927.
Fail to reject the claim of equal means. The data do not provide sufficient evidence to conclude that there is a difference in the true mean weight loss produced by the three exercise programs.

6) At the 0.025 significance level, test the claim that the three brands have the same mean if the
following sample results have been obtained.

Brand ABrand BBrand C
322722
342425
373332
333022
3621
39

H0: \({\mu _1}\) = \({\mu _2}\) = \({\mu _3}\). H1: The means are not all equal.
Test statistic: F = 12.1230. Critical value: F = 5.0959.
Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the three brands have the same mean.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Provide an appropriate response.
7) Fill in the missing entries in the following partially completed one-way
ANOVA table.

SourcedfSSMS=SS/dfF
Treatment21.1
Error203.1
Total25

SourcedfSSMS=SS/dfF
Treatment521.14.221.36
Error2062.03.1
Total2583.1

SourcedfSSMS=SS/dfF
Treatment4521.10.47306.29
Error2062.03.1
Total2583.1

SourcedfSSMS=SS/dfF
Treatment521.14.220.73
Error2062.03.1
Total2521.26

SourcedfSSMS=SS/dfF
Treatment521.14.221.36
Error2062.03.1
Total2583.1

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.

8) Use the data given below to verify that the t test for independent samples and the ANOVA
method are equivalent.

AB
8574
8172
7365
9183
6459

i) Use a t test with a 0.05 significance level to test the claim that the two samples come from populations with the same means.
ii) Use the ANOVA method with a 0.05 significance level to test the same claim.
iii) Verify that the squares of the t test statistic and the critical value are equal to the F test statistic and critical value.

i) An F test of homogeneity of variance suggests equal population variances. The F test statistic =
1.3349; the F critical value = 9.6045. Therefore, the pooled variance model applies. Since t = 1.315 < t0.025(8) = 2.306, accept the claim that the two samples come from populations with the same means.
ii) Since F = 1.73 < F0.05(1, 8) = 5.32, accept the claim that the two samples come from populations with
the same means.
iii) \({t^2}\) = 1.315^2 = 1.73 = F and t0.025(8)^2= 2.306^2 = 5.32 = F0.05(1, 8)

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